The orbital velocity in meters per second. Note: assume the average radius of the earth is 6, Solution to question 2: It is actually easier to answer the three parts of this question backwards, beginning with the orbital velocity, then calculating the period, and hence the orbital angular velocity. One revolution of the earth covers o or 2p radians.

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The orbital velocity in meters per second. Note: assume the average radius of the earth is 6, Solution to question 2: It is actually easier to answer the three parts of this question backwards, beginning with the orbital velocity, then calculating the period, and hence the orbital angular velocity.

One revolution of the earth covers o or 2p radians. Hence 2p radians are covered in 5, From above, the orbital velocity was 7. The same satellite in question 2 above km circular orbit carries a MHz transmitter.

Determine the maximum frequency range over which the received signal would shift due to Doppler effects if received by a stationary observer suitably located in space. Note: the frequency can be shifted both up and down, depending on whether the satellite is moving towards or away from the observer. You need to determine the maximum possible change in frequency due to Doppler i.

If an earth station on the surface of the earth at mean sea level, 6, km from the center of the earth, can receive the MHz transmissions down to an elevation angle of 0 o , calculate the maximum Doppler shift that this station will observe. Solution to question 3 a. The highest Doppler shift would be observed in the plane of the satellite at the orbital height of the satellite: the satellite would be coming directly at the observer or directly 2- 2 away from the observer.

The maximum Doppler shift would therefore be the sum of these two values. The orbital velocity was calculated in question 2 as 7, Using equation 2.

It is best to draw a diagram to see what the set up looks like. Below is a view from above the orbit of the satellite orthogonal to the orbital plane.

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